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About the quantum vacuum lepton/photon ratio

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Results

As demonstrated in [1], G is a function of the ZPE DME and, per extension, of the QV-energy content.  Hereunder, it will be shown, how it is possible to calculate from Coulomb’s Constant (C), the charge contained in QV, known as “virtual pairs”.

Considering the units of C (Nm2/C2) and using the same method as Max Planck, when he developed his natural units (and per extension, the same method as used in [1]), we break down the units of C into Planck units as follows:

 

            ,                          (1)

where: F = a force, E = an energy, and the value “q” represents in this context per definition, the charge that is confined within a Planck volume, therefore making it legitimate to denominate this, “Planck charge” (qP).

Finding “qP” and substituting the values of the other Planck units (all values hereunder being of the MKS metric system):

          . (2)

To convert the above qP into the corresponding amount of leptons (where electrons and positrons = virtual pairs), we divide qP by the charge of the electron (1.6022x10-19 C), thus obtaining the amount of 11.71 leptons per Planck volume. These 11.71 leptons are then multiplied by the mass of the electron (me = 9.1094x10-31 kg), corresponding to a lepton mass equivalent (mq,P) of 1.0667x10-29 kg in a Planck volume.

Finally, since in the ZPE DME (mP/l3P), mP represents an electromagnetic (EM) radiation, by dividing mq,P through mP, we obtain the QV-lepton/photon ratio:

                                          .                                  (3)

Consequently, in QV, leptons (virtual pairs) are approximately only 4.9x10-20 % as frequent as photons (ZPE), what was already known qualitatively in vacuum research.

 

  
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